A greenhouse gas mixture contains 88.0 g of carbon dioxide ( , molar mass = 44.0 g/mol), 48.0 g of oxygen ( , molar mass = 32.0 g/mol), and 36.0 g of water vapor ( , molar mass = 18.0 g/mol). The total pressure of the mixture is 150 kPa. Calculate the partial pressure of in the greenhouse (rounded to integer).
Answer & Analysis
Analysis
Question Analysis
This question involves converting the mass of three distinct gases to moles, calculating total moles of the mixture, and applying the mole fraction form of Dalton’s Law of Partial Pressures. The main focus is on integrating stoichiometric mass-mole conversion with partial pressure calculation for a real-world gas mixture.
Key Concept Explanation
For mass-based multi-component gas mixtures, the core steps are consistent:
1. Convert the mass of each gas to moles using (where = mass, = molar mass).
2. Calculate the total moles of the mixture by summing the moles of all components.
3. Determine the mole fraction of the target gas ( ) and use it to find partial pressure via .
This method is valid only for non-reacting ideal gas mixtures.
Step-by-Step Solution
1. Calculate moles of each gas:
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