A gas mixture contains 71.0 g of chlorine gas ( , molar mass = 71.0 g/mol), 32.0 g of methane ( , molar mass = 16.0 g/mol), and 44.0 g of carbon dioxide ( , molar mass = 44.0 g/mol). The total pressure of the mixture is 9.0 atm. What is the partial pressure of ?
Options
A
1.8 atm
B
2.7 atm
C
3.6 atm
D
2.3 atm
Answer & Analysis
Answer
D
Analysis
Question Analysis
This question involves converting the mass of three distinct gases (chlorine, methane, carbon dioxide) to moles, calculating total moles of the mixture, and applying the mole fraction form of Dalton’s Law of Partial Pressures. The main focus is on integrating stoichiometric mass-mole conversion with partial pressure calculation for a mixture that includes a halogen gas and covalent compounds.
Key Concept Explanation
For mass-based gas mixture problems, the core steps follow these principles:
1. Calculate moles of each gas using the formula , where = mass of the gas and = molar mass of the gas.
2. Sum the moles of all components to get the total moles of the mixture ( ).
3. Calculate the mole fraction of the target gas: .
4. Find the partial pressure of the target gas via Dalton’s Law: .
This method is valid only for non-reacting ideal gas mixtures.
Step-by-Step Solution
1. Calculate moles of each gas:
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