A gas mixture contains 16.0 g of methane ( , molar mass = 16.0 g/mol), 44.0 g of carbon dioxide ( , molar mass = 44.0 g/mol), and 28.0 g of carbon monoxide ( , molar mass = 28.0 g/mol). The total pressure of the mixture is 5.4 atm. What is the partial pressure of ?
Options
A
1.2 atm
B
1.8 atm
C
2.4 atm
D
3.0 atm
Answer & Analysis
Answer
B
Analysis
Question Analysis
This question involves converting the mass of three distinct gases (methane, carbon dioxide, carbon monoxide) to moles, calculating total moles of the mixture, and applying the mole fraction form of Dalton’s Law of Partial Pressures. The main focus is on integrating stoichiometric mass-mole conversion with partial pressure calculation for a multi-component system of carbon-based gases.
Key Concept Explanation
For mass-based gas mixture problems, the core steps are:
1. Convert mass to moles using the formula , where = mass of the gas and = molar mass of the gas.
2. Calculate the mole fraction of the target gas: , where = moles of target gas and = total moles of the mixture.
3. Find partial pressure via Dalton’s Law: .
This method is valid only for non-reacting ideal gas mixtures.
Step-by-Step Solution
1. Calculate moles of each gas:
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