A gas mixture contains 6.0 g of helium ( , molar mass = 4.0 g/mol), 28 g of nitrogen ( , molar mass = 28 g/mol), and 32 g of oxygen ( , molar mass = 32 g/mol). The total pressure of the mixture is 4.0 atm. What is the partial pressure of ?
Options
A
0.8 atm
B
1.0 atm
C
1.1 atm
D
2.0 atm
Answer & Analysis
Answer
C
Analysis
Question Analysis
This question involves converting the mass of three different gases to moles, calculating the total moles of the mixture, and then using the mole fraction form of Dalton’s Law to find the partial pressure of a target gas. The main focus is on integrating stoichiometric mass-mole conversion with partial pressure calculation for a multi-component gas system.
Key Concept Explanation
For mass-based gas mixture problems, the core steps rely on two relationships:
1. Moles calculation: , where = mass of the gas and = molar mass of the gas.
2. Dalton’s Law via mole fraction: , where (mole fraction of gas ), = partial pressure of gas , and = total pressure of the mixture.
This approach is only valid for non-reacting ideal gas mixtures.
Step-by-Step Solution
1. Calculate moles of each gas:
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