A gas mixture contains 12.0 g of helium ( , molar mass = 4.0 g/mol), 28.0 g of nitrogen ( , molar mass = 28 g/mol), and 48.0 g of oxygen ( , molar mass = 32 g/mol). The total pressure of the mixture is 3.6 atm. What is the partial pressure of ?
Options
A
0.8 atm
B
1.0 atm
C
1.6 atm
D
2.0 atm
Answer & Analysis
Answer
B
Analysis
Question Analysis
This question involves converting the mass of three gases to moles, calculating total moles of the mixture, and applying the mole fraction form of Dalton’s Law of Partial Pressures. The main focus is on integrating stoichiometric mass-mole conversion with partial pressure calculation for a multi-component system.
Key Concept Explanation
To solve mass-based partial pressure problems, follow two core steps:
1. Convert mass of each gas to moles using the formula , where = mass and = molar mass.
2. Calculate partial pressure using mole fraction: , where .
This method applies only to non-reacting ideal gas mixtures.
Step-by-Step Solution
1. Calculate moles of each gas:
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