Given the electronegativity values of phosphorus (P, EN = 2....

Question Analysis
This question tests the student's ability to calculate the electronegativity difference (ΔEN) and use it to predict the type of chemical bond formed between two elements.

Key Concept Explanation
ΔEN determines bond type:
ΔEN = 0–0.4 → Nonpolar covalent
ΔEN = 0.4–1.7 → Polar covalent
ΔEN ≥ 1.7 → Ionic

Step-by-step Solution
1. Identify the electronegativity values: P = 2.19, S = 2.58.
2. Calculate ΔEN: ΔEN = 2.58 − 2.19 = 0.39.
3. Determine bond type: 0.39 is within ...

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