Chemistry

Question Analysis
This question involves identifying the Period 3 element with the lowest first ionization energy using the period trend. The main focus is on applying the left-to-right trend to specific elements.

Key Concept Explanation
First ionization energy increases from left to right across a period. The leftmost element in a period has the largest atomic radius and weakest hold on valence electrons, resulting in the lowest ionization energy.

Step-by-Step Solution
1. Recall the order of Period 3 elements: Na (leftmost) → Mg → Al → ... → Ar.
2. Apply the period trend: leftmost element = lowest ionization energy.