Question Analysis
This problem evaluates the understanding of the end behavior of power functions, specifically for even degrees and negative leading coefficients.
Key Concept Explanation
For a power function of the form , where is a constant and is a positive integer, the end behavior depends on the sign of and the parity of . If is even and is negative, as , , meaning the graph opens downwards.
Step-by-step Solution
1. Identify the degree and the leading coefficient of the function
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