A box contains 12 red balls, 8 blue balls, and 5 green balls. If one ball is drawn at random, what is the probability that it is either red or blue?
Options
A
B
C
D
Answer & Analysis
Answer
C
Analysis
Question Analysis
This question involves calculating the probability of mutually exclusive events (drawing red or blue balls).
The main focus is applying the addition rule for mutually exclusive events: .
Key Concept Explanation
Since a ball cannot be both red and blue, these events are mutually exclusive.
The probability of their union is the sum of their individual probabilities.
Step-by-Step Solution
Total balls:
,
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