Geometry

Question Analysis
This question involves calculating the probability of non - mutually exclusive events.
The main focus is on identifying the individual probabilities of each event and the probability of their intersection, then applying the formula for non - mutually exclusive events.

Key Concept Explanation
For non - mutually exclusive events A and B, the probability of A or B is given by P(A ∪ B) = P(A) + P(B) - P(A ∩ B).
Here, event A is drawing a red ball, and event B is drawing a ball with an even number.

Step-by-Step Solution
The number of red balls n(R) = 5, so P(R) = 5/10 = 0.5.
The number of balls with even numbers n(E) = 5, so P(E) = 5/10 = 0.5.
The number of red balls with even numbers n(R ∩ E) = 2, so P(R ∩ E) = 2/10 = 0.2.
Using the formula P(R ∪ E) = P(R) + P(E) - P(R ∩ E) = 0.5 + 0.5 ...