A basket holds 10 toys, 4 are teddy bears and 6 are toy cars. Two toys are drawn without replacement. What is the probability that the first toy is a teddy bear and the second toy is a toy car?
Options
A
B
C
D
Answer & Analysis
Answer
A
Analysis
Question Analysis
This question focuses on calculating the probability of two successive dependent events in a straightforward scenario.
The key is to correctly apply the multiplication rule for dependent events while accounting for the change in the sample space after the first draw.
Key Concept Explanation
Dependent events mean that the outcome of the first toy draw impacts the probability of the second draw.
The multiplication rule for dependent events, , is used here.
Step-by-Step Solution
Calculate the probability of drawing a teddy bear on the first draw:
There are 4 teddy bears out of 10 total toys, so .
Calculate the probability of drawing a toy car on the second draw given that a teddy bear was drawn on the first draw:
After removing one teddy bear, there are 9 toys left, and 6 of them are toy cars. So
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