A box contains 3 red balls, 2 blue balls, and 1 green ball. A ball is drawn, replaced, and then this process is repeated two more times. What is the probability of getting a red ball on the first draw, a blue ball on the second draw, and a green ball on the third draw?
Options
A
1/36
B
1/12
C
1/6
D
1/2
Answer & Analysis
Answer
A
Analysis
Question Analysis
This question involves calculating the joint probability of three independent events that occur during sequential ball draws with replacement.
The main focus is on correctly determining the individual probabilities of each draw and applying the multiplication rule for independent events to find the combined probability.
Key Concept Explanation
Independent events are those where the outcome of one event does not influence the outcome of the others.
For multiple independent events , , and , the probability of all of them occurring is given by the formula .
When drawing a ball with replacement, the probability of drawing a particular ball remains constant for each draw.
Step-by-Step Solution
Calculate the probability of each draw:
The total number of balls is .
The probability of getting a red ball on the first draw, .
The probability of getting a blue ball on the second draw,
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