Triangle XYZ has vertices X(-24, 32), Y(-32, 40), Z(-40, 48)...

Question

Triangle XYZ has vertices X(-24, 32), Y(-32, 40), Z(-40, 48). Dilate it by centered at the origin. Find the new vertices.

A

X'(3, -4), Y'(4, -5), Z'(5, -6)

B

X'(6, -8), Y'(8, -10), Z'(10, -12)

C

X'(10, -15), Y'(-15, 20), Z'(-20, 25)

D

X'(15, -20), Y'(20, -25), Z'(25, -30)