Geometry

Question Analysis:
This problem requires working backwards from the reflection result to determine properties of the original point.

Key Concept Explanation:
For a point (x,y):
Reflection across y = -x gives (-y, -x)
Quadrant III requires both coordinates negative: -y < 0 and -x < 0

Step-by-Step Solution:
Let original point be T(a, b)
After reflection: T'(-b, -a)
For T' to be in Quadrant III:
-b < 0 ⇒ b > 0
-a < 0 ⇒ a > 0

Option Analysis:
A. Correct (matches a>0, b>0)
B. Incorrect (would place T' in QIV)
C. Incorrect (would place T' in QII)<...