Biology

The correct answer is: B.0.48.

 

Explanation:

Under Hardy-Weinberg equilibrium, the frequency of heterozygous individuals (genotype Aa) is calculated using the formula 2pq, where:

1.p is the frequency of the dominant allele A,

2.q is the frequency of the recessive allele a.

 

Given p = 0.6, we can calculate q as:

q = 1 - p = 1 - 0.6 = 0.4

 

Now, the frequency of heterozygous individuals is:

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