To solve this problem, let’s analyze it
step by step using the principles of elastic collisions and energy
conservation.
Velocities before the collision:
Both balls are dropped from height h, so
their velocity just before reaching the ground is calculated using energy
conservation:
When ball B collides elastically with the
ground, it reverses direction without losing speed because the ground is much
more massive. After rebounding, ball B has a velocity:
(Negative sign indicates the upward
direction.)
Collision between ball A and ball B:
Now, ball A and the rebounding ball B
collide elastically. Before the collision:
Ball A's velocity:
(downward, positive direction)
Ball B's velocity:
(upward, negative direction)
For an elastic collision, we use the
conservation of momentum and kinetic energy.
The conservation of momentum gives
, where and are the
velocities of ball A and ball B just after the collision.
Substituting ,
, and into the momentum - conservation
equation:
.
For an elastic collision, kinetic - energy
conservation
.
Substituting ,
, and :
From , we have
.
Substitute