Let's analyze each function one by one to determine which one represents the graph:
A.Function
First, we factor the numerator: . Then the function can be written as:
For , we can cancel out the common factor , and we get .
This means that the function simplifies to a linear function , but it has a hole at . When , , so it passes through the origin. Also, since the slope of is , it is an increasing function. This function exactly matches the graph.
B.Function
Factor the denominator: . So the function becomes .
For and , we can simplify it to .
This function has vertical asymptotes at