Algebra-2

To solve ∣x − 1∣ + ∣x + 2∣ = 5, consider the intervals based on the critical points x = 1 and x = −2:

For x < −2: −(x − 1) − (x + 2) = 5 leads to −2x − 1 = 5  →  x = −3.

For −2 ≤ x < 1: −(x − 1) + ...