Algebra-2

First, rearrange the equation of the second line 3x + 2y = 10 to slope-intercept form.

We get 2y = -3x + 10, and then y = (-3/2)x + 5. The slope of this line is -3/2.

For two lines to be perpendicular, the product of their slopes is -1.

The slope of the second line from 3x + 2y = 10 is -3/2.

So the slope of the first line must be 2/3 ...