Algebra-2

To find the value of ( z ) such that the point (2, -1, z) is a solution to the given system of equations, we will substitute (x = 2) and (y = -1) into each equation and solve for ( z ).

Given System of Equations

1.( x + 2y + z = 5 )   (Equation 1)  

2.( 3x - y + 4z = 27 )   (Equation 2)  

3.( 2x + 3y - z = -4 )   (Equation 3)  

 

Substitute ( x = 2 ) and ( y = -1 ) into the Equations

Step 1: Substitute into Equation 1

Substituting ( x = 2 ) and ( y = -1 ) into Equation 1:

2 + 2(-1) + z = 5

2 - 2 + z = 5

z = 5

 

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