To factor the polynomial 2y³ + 4y² + 6y + 12 using the factor by grouping method, let's follow these steps:
Step 1: Group the terms: (
2y³ + 4y²) + (
6y + 12)
Step 2: Factor out the common factor from each group:
In the first group, we can factor out 2y²: 2y²(y + 2).
In the second group, we can factor out 6: 6(y + 2).
Now, we have:
2y²(y + 2) +
6(y + 2)
Step 3: Notice that (
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