Algebra-1

Given the expression 3n² + 10n + 8, we have:
a = 3
b = 10
c = 8

We need to find two numbers m and n such that their product is ac (3 * 8 = 24) and their sum is b (10).

The numbers that satisfy these conditions are 4 and 6:

m = 4
n = 6

Now, let's rewrite the middle term (10n) using these values:
10n = 4n + 6n

Now we c...