Algebra-1

To find a function that has roots at -6 and 1, we need to check each of the given options by substituting these values into the function and verifying if they result in f(x) equal to zero.

Option A:
f(x)= (x + 6)(x +1）
When we substitute x = -6, we get: f(-6) = (-6 + 6)(-6 + 1) = 0 * -5 = 0.
When we substitute x = 1, we get: f(1) = (1 + 6)(1 + 1) = 7 * 2 = 17.
Option A does not satisfy the condition.

Option B:
f(x)= (x - 6)(x +1）
When we substitute x = -6, we get: f(-6) = (-6 - 6)(-6 + 1) = -12 * -5 = 60.
When we substitute x = 1, we get: f(1) = (1 - 6)(1 + 1) = -5 * 2 = -10.
Option B does not satisfy the condition.

Option C:

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