The transformation x + 3 > -14 AND x + 3 < 14 is equivalent to which absolute value inequality?
The transformation x + 3 > -14 AND x + 3 < 14 is equivalent to |x + 3| < 14.
For |A| < B, where A is an expression and B is a positive number, the compound inequality -B < A < B represents the same set of solutions.
In this case, x + 3 > -14 AND Click "Show Answer" to reveal the answer and analysis
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