Algebra-1

To solve the compound inequalities -3(2x + 1) < -15 and 8x - 15 < 3x + 25, we need to solve each inequality separately and then find the intersection of the two.

Solve the first inequality -3(2x + 1) < -15:

-3(2x + 1) < -15

-3(2x + 1) ÷ (-3) > (-15) ÷ (-3) (divide both sides by -3)

2x + 1 > 5

2x + 1 - 1 > 5 - 1 (subtract 1 from both sides)

2x > 4

2x/2 > 4/2 (divide both sides by 2)

x > 2

Solve the second inequality 8x - 15 < 3x + 25: