Algebra-1

To solve the compound inequalities 11(x + 3) ≤ 66 and 9x + 25 ≥ 7, we need to solve each inequality separately and then find the intersection of the two.

Solve the first inequality 11(x + 3) ≤ 66:

11(x + 3) ≤ 66

11(x + 3) ÷ 11 ≤ 66 ÷ 11 (divide both sides by 11)

x + 3 ≤ 6

x + 3 - 3 ≤ 6 - 3 (subtract 3 from both sides)

x ≤ 3