Algebra-1

To determine which of the given inequalities is not correct when u ≤ 0, we need to evaluate each inequality.

 

Option A, u + 1 ≤ 1

Given u ≤ 0

u + 1 ≤ 0 + 1 (add 1 to both sides)

u + 1 ≤ 1

This inequality is correct.

 

Option B, 2u ≥ 0

Given u ≤ 0

u × 2 ≤ 0 × 2 (multiply both sides by 2)

2u ≤ 0

There is no need to flip the inequality sign because we only performed multiplication by a positive number. So, this inequality is incorrect.

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