Find the right set of values of x for: both 3(3x – 1) <11 and (3x – 3)(3 + x) < 0
For (3x – 3)(3 + x) < 0,
Find roots: x = 1, x = −3
Test intervals: x<−3, −3< x <1, x > 1.
Inequality is negative for −3< x < 1.
Thus -3 < x < 1
For 3(3x – 1) < 11,
Expand: 9x − 3< 11
Solve: 9x < 14
Divide: x< Click "Show Answer" to reveal the answer and analysis
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