Algebra-1

To determine which equation has the solution x = 0, we need to substitute x = 0 into each equation and see which one results in a true statement.

Option A: 1.6x + 2.7 = 2.7 − 0.2x

1.6 × 0 + 2.7 = 2.7 − 0.2 × 0

0 + 2.7 = 2.7 + 0

2.7 = 2.7

This equation is true when x = 0.

Option B: 2.2x − 1.6 = 1.2x − 3.1

2.2 × 0 − 1.6 = 1.2 × 0 − 3.1

0 – 1.6 = 0 – 3.1

-1.6 ≠ -3.1

This equation is not true when x = 0.

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