Algebra-1

To determine which equation has the solution x = 0, we need to substitute x = 0 into each equation and see which one results in a true statement.

Option A: x + 5 = 3x + 7

0 + 5 = 3 × 0 + 7

5 = 5 + 7

5 ≠ 12

This equation is not true when x = 0.

Option B: 2x – 1 = 4x + 32

2 × 0 – 1 = 4 × 0 + 32

0 – 1 = 0 + 32

-1 ≠ 32

This equation is not true when...