Algebra-1

To determine which equation has the solution x = 5, we need to substitute x = 5 into each equation and see if it holds true.

Option A: 4x – 3 = -11

4 × 5 – 3 = 20 – 3 = 17 ≠ 11

This equation does not hold true.

Option B: 3x + 7 = 22

3 × 5 + 7 = 15 + 7 = 22

This equation holds true.

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