Algebra-1

To determine which equation has the solution x = 2, we need to substitute x = 2 into each equation and see if it holds true.

Option A: 6x – 1 = 11

6 × 2 – 1 = 12 – 1 = 11

This equation holds true.

Option B: 4x – 5 = 13

4 × 2 – 5 = 8 – 5 = 3 ≠ 13

This equation does not hold true.

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