Algebra-1

To solve the inequality |3x + 6| ≥ 15, we can break it down into two cases:

Case 1: 3x + 6 is nonnegative (i.e., 3x + 6 ≥ 0)
In this case, the absolute value |3x + 6| is equal to 3x + 6, so we have:
3x + 6 ≥ 15

Solving this inequality, we get:
3x ≥ 15 - 6
3x ≥ 9
x ≥ 3

Case 2: 3x + 6 is negative (i.e., 3x + 6 < 0)
In this case, the absolute value |3x + 6| is equal to -(3x + 6), so we have:
-(3x + 6) ≥ 15

Multiplying both s...