Algebra-1

To solve the quadratic equation y = -x² - 5x + 12 using the quadratic formula, we set the equation equal to zero:

-x² - 5x + 12 = 0

Comparing this equation to the standard form ax² + bx + c = 0, we have:
a = -1
b = -5
c = 12

Substituting these values into the quadratic formula:

$$x=\frac {-(-5)\pm \sqrt {{(-5)}^{2}-4(-1)(12)}} {2(-1)}$$

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