Algebra-1

Let's assume Jenny needs to use "x" liters of the 56% acid solution and "y" liters of the 43% acid solution.

According to the given information, Jenny wants to make 13 L of a 52% acid solution. We can set up the following equation based on the acid concentration:

(0.56x + 0.43y) / (x + y) = 0.52   ---(1)

We also know that the total volume of the solution is 13 L:

x + y = 13   ---(2)

Now we have a system of two equations with two variables. We can solve this system to find the values of x and y.

We can rewrite equation (2) as y = 13 - x and su...