Algebra-1

To determine which line goes through (6, 4) and is perpendicular to , we need to analyze the equations and consider the slopes.

The given line has a slope of . Any line perpendicular to this line will have a slope that is the negative reciprocal of , which is 3.

Let's analyze the options:
A.
The slope of this line is , which is not the negative reciprocal of . Therefore, line A is not perpendicular to .

B. y = 3x + 22
The slope of this line is 3, which is the negative reciprocal of . To check if it passes through (6, 4), we substitute x = 6 and y = 4 into the equation:
4 = 3(6) + 22
4 = 18 + 22
4 = 40
The point (6, 4) does not satisfy the equation. Therefore, line B is perpendicular to

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