Physics

Given:
Distance = 300meters (heigh of 300 meters)
Acceleration = 9.8 m/s² (Acceleration due to gravity)
Initial velocity = 0m/s
(In this scenario, the phone is dropped from rest, which means its initial velocity (v₀) is 0 m/s. When an object is dropped from rest, it starts its motion from a state of rest, so its initial velocity is zero.)

To determine the velocity of the phone travels when it hits the ground, we can use the equation:
Vf² = Vi² + 2ad

Where:
Vf is the final velocity,
Vi is the initial velocity,
a is the accel...